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So the bracket is going to be cut out from a steel plate in a weird, rounded out triangular shape, and then a hole will be drilled through it. For simplicity though, lets just say the bracket is a ring with one half of it welded onto a wall. OD of the ring is 1.25", ID is 0.765", which results in a thickness of 0.2425".

The equation for tensile stress is

*σ = Fn*

*/ A.*

Since the bracket is going to be pushed and pulled, the cross sectional area is:

(0.2425" * H) * 2, where H is the height of the ring when it is placed on the table, which is the thickness of the steel plate I need to cut the brackets out from. Equation simplifies to 0.485H.

The worst case scenario this bracket has to endure is 2 metric tons, which translates to 4410lbs

The yield strength of the steel plate I intend to use is 36,000psi. As I understand, 0.6 represents the ratio of maximum bending stress to yield stress for the material, so I'm guessing it is the same for maximum tensile stress? Which makes the maximum allowable stress 21600psi.

So if we solve for H,

H = 4410 / (0.485 * 21600) = 0.421", so if I get a steel plate that is 0.5" thick to cut my brackets out from I should be fine.