Circles on XY, YZ and XZ planes from a Sphere

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SUMMARY

The discussion focuses on deriving the equations for circles formed by the intersection of spheres with the XY, YZ, and XZ planes. A sphere is defined by the equation (x-cx)²+(y-cy)²+(z-cz)²=r², where (cx, cy, cz) is the center and r is the radius. When intersecting with the XY plane (z=0), the resulting equation simplifies to (x-cx)²+(y-cy)²=r², representing the circle's equation. The user seeks clarification on the intersection of spheres with multiple planes within a cuboid structure.

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  • Understanding of 3D geometry and spatial relationships.
  • Familiarity with the equation of a sphere in Cartesian coordinates.
  • Knowledge of plane equations in 3D space.
  • Basic skills in mathematical simplification and manipulation of equations.
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  • Research the mathematical derivation of circle equations from sphere-plane intersections.
  • Explore 3D graphics programming using libraries like OpenGL or Three.js for visualizing spheres and planes.
  • Investigate the implications of multiple intersections in 3D space, particularly in cuboid structures.
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Mathematicians, 3D graphics developers, and anyone involved in computational geometry or physics simulations who needs to understand sphere-plane intersections.

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I want to find the equations for the circles (formed on the planes) when a sphere cuts the XY, YZ and XZ planes. What I am trying to achieve is a software application that will have a 3D cuboid and inside this cuboid there will be many spheres. Now I want to find the circles created by these spheres when they intersect with the planes. Thank you.
 
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Any sphere? Then you'll have some equation in the unknowns x,y,z that defines which points (x,y,z) belong to the sphere. The points in the XY plane also must fulfil z=0, so you'll get a new equation in x and y only. That describes the first circle you're looking for.
 
Suppose there is a sphere with a certain radius in this cuboid and it only intersects with the YZ plane. There is another sphere that has some radius and it intersects with any two planes and so on...
 
I'm not quite sure what you're starting off with. When you have a sphere of radius r and centre (cx,cy,cz), this sphere is formed of all points (x,y,z) with (x-cx)2+(y-cy)2+(z-cz)2=r2. The points on the XY plane also fulfil the equation z=0. Put those two together, and you get (x-cx)2+(y-cy)2=r2, i.e. the equation of the circle in which the sphere intersects the plane.

Is that what you meant?
 
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Thanks a lot Michael for your replies and help. If I have a cuboid (front, back, top, bottom, left and right planes) will there be two XY (front OR back), two YZ(left OR right) and two XZ (top OR bottom) planes ? Or am I thinking wrong.

Now keeping my confusion in mind, can you tell me if the sphere intersects the XY plane (which I am thinking of as the front OR back), does your previous answer hold. I mean the equation you had provided. I think you will need to explain to me like a child :-)
 

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