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Homework Help: Circuit Analysis and resistance

  1. Jan 1, 2010 #1
    http://img41.imageshack.us/img41/7798/circuitanalysis.png [Broken]

    1. The problem statement, all variables and given/known data

    (a) What is the equivalent resistance of the network of resistors in Figure 6.13?
    (b) What current exists in the 3.0 Ω resistor?

    R1=2ohms, R2=6ohms, R3=6ohms, R4=6ohms, R5=6ohms, R7=3ohms, V1=6V

    2. Relevant equations

    V=IR
    1/Rt=1/R1+1/R2+1/R3...

    3. The attempt at a solution

    (a)The diagonal resistor confused me.

    1/Rt1=1/2+1/6
    Rt1=1.5ohms

    1/Rt2=1/6+1/6+1/6+1/6
    Rt2=1.5ohms

    Rt=1.5+1.5+3.0=6.0ohms

    (b)Tried, but may be wrong way to do it.

    V=IR
    I=V/R
    I=6.0V/6.0ohms
    I=1.0A
     
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Jan 1, 2010 #2

    diazona

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    Homework Helper

    In that case, redraw the circuit yourself, so that resistor isn't diagonal. Then look for a pair of resistors that is in series or a pair that is in parallel. (By the way: you didn't write the equation for combining resistors in series, but do you know what it is?)
     
  4. Jan 1, 2010 #3
    Rt=R1+R2+R3...
     
  5. Jan 1, 2010 #4

    diazona

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    Homework Helper

    Cool, just checking. You will have to use that.
     
  6. Jan 2, 2010 #5
    The two resistors at the top right hand corner are in series and the resultant is in parallel with diagonal resistor.
     
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