# Homework Help: Circuit Analysis and resistance

1. Jan 1, 2010

### gnarrr

http://img41.imageshack.us/img41/7798/circuitanalysis.png [Broken]

1. The problem statement, all variables and given/known data

(a) What is the equivalent resistance of the network of resistors in Figure 6.13?
(b) What current exists in the 3.0 Ω resistor?

R1=2ohms, R2=6ohms, R3=6ohms, R4=6ohms, R5=6ohms, R7=3ohms, V1=6V

2. Relevant equations

V=IR
1/Rt=1/R1+1/R2+1/R3...

3. The attempt at a solution

(a)The diagonal resistor confused me.

1/Rt1=1/2+1/6
Rt1=1.5ohms

1/Rt2=1/6+1/6+1/6+1/6
Rt2=1.5ohms

Rt=1.5+1.5+3.0=6.0ohms

(b)Tried, but may be wrong way to do it.

V=IR
I=V/R
I=6.0V/6.0ohms
I=1.0A

Last edited by a moderator: May 4, 2017
2. Jan 1, 2010

### diazona

In that case, redraw the circuit yourself, so that resistor isn't diagonal. Then look for a pair of resistors that is in series or a pair that is in parallel. (By the way: you didn't write the equation for combining resistors in series, but do you know what it is?)

3. Jan 1, 2010

### gnarrr

Rt=R1+R2+R3...

4. Jan 1, 2010

### diazona

Cool, just checking. You will have to use that.

5. Jan 2, 2010

### sArGe99

The two resistors at the top right hand corner are in series and the resultant is in parallel with diagonal resistor.