The problem statement: To save on heating costs, the owner of a greenhouse keeps 800kg of water around in barrels. During a winter day, the water is heated by the sun to 50 degrees Fahrenheit. During the night the water freezes into ice at 32 degrees Fahrenheit in 10 hours. An electrical heating system is used providing the same heating effect as the water. The attempt at a solution: P=Q/t = (542*10^6)/36000s = 15066 Watts I=P/V = 15066/240 = 62.77Amperes The minimum ampere rating that the 240 volt circuit breaker would have to be to avoid tripping is what i calculated....it turned out to be 62.77Amperes. The question: What I don't get is "does the circuit breaker trip? Why or why not?"