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## Homework Statement

Find Voltage across a and b and the missing current (i)

so this is the circuit

http://img3.imageshack.us/img3/184/circuitsf.jpg [Broken]

## Homework Equations

KCL and KVL

current towards the node is + away is -

Et = E1 + E2 + E3 in series

Et = E1 = E2 = E3 in parallel

Ohms law

E= IR

## The Attempt at a Solution

KCL @ node c

3A-i1-i2= 0

i2=6V/3Ohms

i2=2A

3A-2A=i1

i1=1A

KCL @ node d

i2+1A-1A-i3=0

2A+1A-1A=i3

i3=2A

KCL @ node e

i3+i4-i

i4=24V/4Ohms

i4=6A

2A+6A=i

i=8A

KVL @ loop acdeba

E(ab)+i1(8)-6V-i3(12)+12V=0

E(ab)=-8V+6V+24V-12V

E(ab)=10V

so thats what i try..

my question is.. is those current direction is right?.. XD still dont know if i did it right..

so anyone who can help?

and the Voltage across AB.. am i right in having the loop acdeba.. neglecting the resitor which have 24V?

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