Circuit with 2 Batteries and 6 Resistors

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SUMMARY

The discussion centers on analyzing a circuit with two batteries (V1 = 18 V and V2 = 12 V) and six resistors (R1 = R5 = 56 Ω, R2 = R6 = 157 Ω, R3 = 118 Ω, R4 = 97 Ω). Participants apply Kirchhoff's laws to derive equations for the circuit, specifically focusing on the relationships between currents (I1, I2, I3, I4, I5, I6) and voltages across the resistors. The key equations established include I4R4 + I6R6 = V2 and R5I5 + R4I4 + R6I6 + R2I2 + R3I3 = V1. The discussion emphasizes the importance of understanding the voltage across resistors R4 and R5 to solve for the current I3.

PREREQUISITES
  • Understanding of Kirchhoff's laws (junction and loop rules)
  • Familiarity with Ohm's Law (V=IR)
  • Basic knowledge of circuit analysis techniques
  • Ability to interpret circuit diagrams
NEXT STEPS
  • Study advanced applications of Kirchhoff's laws in complex circuits
  • Learn about Thevenin's and Norton's theorems for circuit simplification
  • Explore techniques for analyzing circuits with multiple power sources
  • Investigate the impact of resistor configurations (series vs parallel) on circuit behavior
USEFUL FOR

Students studying electrical engineering, circuit designers, and anyone seeking to deepen their understanding of circuit analysis involving multiple resistors and power sources.

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Homework Statement



A circuit is constructed with six resistors and two batteries as shown. The battery voltages are V1 = 18 V and V2 = 12 V. The positive terminals are indicated with a + sign, The values for the resistors are: R1 = R5 = 56 Ω, R2 = R6 = 157 Ω R3 = 118 Ω, and R4 = 97 Ω. The positive directions for the currents I1, I2 and I3 are indicated by the directions of the arrows. What is V4?

Homework Equations



V=IR

The Attempt at a Solution



I have been trying to apply Kirchoff's laws for junctions and loops.

I picked 2 loops and got the following equations-

I4R4 +I6R6 = V2

R5I5 + R4I4 + R6I6 + R2I2 + R3I3 = V1

From the junction rule, I got that I1 + I3 = I5 = I2

I'm not sure if this is right though- I5 = I2 = I4 = I6

I don't know what to do next. I think I need another equation.
 

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I think you need to step back from the analysis for a moment and ask yourself, "what is determining the voltage across resistors R4 and R5?"
 
Your picture is so small it's illegible. Can you post a bigger version?
 
vela said:
Your picture is so small it's illegible. Can you post a bigger version?

If you click on it, I think it gets bigger.
 
Okay, I got that part. Now, to find I3, can I use my equations and Kirchoff's laws?
 
Never mind! Got it! The problem also asks for the potential difference between V(a) and V(b).

Is this just V=IR where R= R6 and I=I2?
 
Yes, that's right.
 
How'd you figure out I3?
 

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