Circuits - Transfer function of this LRC circuit

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wcjy
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Homework Statement
Given the following circuit with the inductor L1= 8(H). The transfer function between Vo(s) and Vs(s) can be described as:
$$\frac{V_o(s)}{V_s(s)} = \frac{1}{as^3+bs^2+cs+d}$$

Find a, b, c and d in this equation. Change the inductor by L1 by another inductor L2 = B(H) such that the system has a pole at S = -2/3. Find B
Relevant Equations
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Circuit schematic of a ladder network: voltage source Vs feeds R1 (1 Ω) in series, then shunt C1 (1 F), series L1, shunt C2 (500 mF), shunt R2 (1 Ω) and shunt C3 (500 mF), with output voltage Vo across C3.

Handwritten circuit schematic with source Vs, series inductor 8s, capacitors 1/s and 2/s, resistor 1, and output Vo; below it, nodal analysis at V1(s) leading to V1(s) = (Vs + Vo(s)/8s) / (1 + s + 1/8s).
Handwritten KCL at V0(s) on a dark background: (V0(s) - V1(s))/8s + V0(s)/(2/5) + V0(s)/1 + V0(s)/(2/5) = 0, then V0 [1/8s + s/2 + 1 + s/2] = V1(s)/8s.
Handwritten KCL at Vo(s) on a dark background: (Vo(s) - V1(s))/8s + Vo(s)/(2/s) + Vo(s)/1 + Vo(s)/(2/s) = 0, then Vo [1/8s + s/2 + 1 + s/2] = V1(s)/8s.
Handwritten derivation of a transfer function: substituting V1(s) into the node equation, expanding the bracketed terms, and arriving at Vo/Vs = 1/(8s^3 + 16s^2 + 10s + 3).


Got B = 9.

My school doesn't provide answers, hence could someone double check if my answers is right? Thanks!
 
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Looks good, but I think that you miscopied the constant 2 as a 3 in the final line of your derivation.
 
gneill said:
Looks good, but I think that you miscopied the constant 2 as a 3 in the final line of your derivation.
thank you so much!