Circuits - Variables dependent on R?

In summary: I'm curious how you did it.In summary, the circuit of interest is attached. The question is to solve for I1, I2, I3, I4, and V_diode. I did it by simplifying the circuit and using the superposition theorem. V_diode can only be zero or negative, so I_3 was 0 and the node for Vdiode(-) was the wire between the 3 resistors.
  • #1
pyroknife
613
4
The circuit of interest is attached.
The question is to solve for I1, I2, I3, I4, and V_diode.

My question is will the variables come out to be numbers or dependent on R?This is how I did it and it depends on R:
I3=0 b/c of the open.
The branch with the open is pretty much not there.
Thus,
KCL: I1+I2=I4
KVL gives 2 equations:
1-2R*I1+R*I2=0
-R*I2-R*I4+1=0

So I guess I1, I2, I4, and V_diode will not solve to be numbers and will depend on R? Or did I do this all wrong?
 

Attachments

  • Untitled.png
    Untitled.png
    3.3 KB · Views: 412
Last edited:
Physics news on Phys.org
  • #2
How is the diode hooked up? Cathode to + or the other way?
 
  • #3
rude man said:
How is the diode hooked up? Cathode to + or the other way?

The diode is hooked up so with the way I_3 is drawn, it would cause the 'ideal' diode to become an open. I'm not sure how to describe that in terms of the cathode.
 
  • #4
pyroknife said:
The diode is hooked up so with the way I_3 is drawn, it would cause the 'ideal' diode to become an open. I'm not sure how to describe that in terms of the cathode.

So i3 can only be zero or negative?
 
  • #5
rude man said:
So i3 can only be zero or negative?

I_3 is 0 because that branch of the circuit technically doesn't exist.
 
  • #6
pyroknife said:
I_3 is 0 because that branch of the circuit technically doesn't exist.

Then why does the question ask for I3? Are you sure you have stated the question accurately?
 
  • #7
I don't see why it can't ask for I3.
I_3 is simply 0. That's the answer for I3, only 1 of the 5 variables to be solved.
I still need to solve for I1, I2, I4, v_diode.
 
  • #8
OK, so the first thing is to simplify the circuit by removing irrelevant components.
 
  • #9
Do you know the superposition theorem?
 
  • #10
rude man said:
Do you know the superposition theorem?

Yes, but everything in class and tests will be done from using KVL and KCL. So those are the things I would prefer to use.

Wouldn't superposition give me the same answer as my original post?


I attached a new drawing with the resistor removed. I kept the V_diode in there though.
 

Attachments

  • Untitled.png
    Untitled.png
    3 KB · Views: 384
  • #11
Good first step. Now, looking at the original schematic, can you identify one of your new nodes with Vdiode(-)? Let us call the node Vdiode(+) = zero volts, shall we.
 
  • #12
rude man said:
Good first step. Now, looking at the original schematic, can you identify one of your new nodes with Vdiode(-)? Let us call the node Vdiode(+) = zero volts, shall we.


The node would be the wire between the 3 resistors.

But I still think you answer will not solve to be a number and will still depend on R.
 
  • #13
pyroknife said:
The node would be the wire between the 3 resistors.

But I still think you answer will not solve to be a number and will still depend on R.

You are correct on both counts. How could the answer not depend on R?
 
  • #14
rude man said:
You are correct on both counts. How could the answer not depend on R?

What I mean by that is if I1, I2, I4, and Vdiode will come out as actual numbers (i.e R ends up canceling out somewhere in the equation and you're left with actual numbers) or if it will come out as involving the variable 'R.'

i.e Vdiode maybe something like Vdiode=2R instead of something like 10V
 
Last edited:
  • #15
The equations for the currents will all involve variable R.
 
  • #16
pyroknife said:
What I mean by that is if I1, I2, I4, and Vdiode will come out as actual numbers (i.e R ends up canceling out somewhere in the equation and you're left with actual numbers) or if it will come out as involving the variable 'R.'

i.e Vdiode maybe something like Vdiode=2R instead of something like 10V

Not possible. You can't get around I = V/R. V is a number so I must involve R.

What level are you at in your studies?
 
  • #17
3rd year undergrad. Why?
 
  • #18
pyroknife said:
3rd year undergrad. Why?

I ask that question a lot to determine how to respod to questions. Sometimes I have to revert to basics, other times I can assume more advanced knowledge.

Are you in an engineering or science curriculum?
 
  • #19
rude man said:
I ask that question a lot to determine how to respod to questions. Sometimes I have to revert to basics, other times I can assume more advanced knowledge.

Are you in an engineering or science curriculum?

Yes, my major is mechanical and aerospace engineering. I've taken quite a bit of physics and circuits courses when I was in high school and during my freshman year, but also forgot quite a bit. Currently, I'm taking a mechatronics course, which is where this problem came from.

I just solved this system and it was much easier than I thought it would be.
 

FAQ: Circuits - Variables dependent on R?

What is resistance and how does it affect dependent variables in a circuit?

Resistance is the measure of how much a material or component impedes the flow of electric current. In a circuit, resistance can affect dependent variables, such as voltage and current, by reducing their values.

How do changes in resistance impact the behavior of a circuit?

Changes in resistance can have a significant impact on the behavior of a circuit. For example, an increase in resistance can decrease the flow of current, while a decrease in resistance can increase the flow of current. This can also affect the voltage and power in the circuit.

What factors can affect the resistance in a circuit?

There are several factors that can affect the resistance in a circuit, including the type of material the circuit is made of, the length and thickness of the wire, and the temperature of the circuit. Additionally, the presence of other components, such as resistors, can also impact the overall resistance of the circuit.

How can we calculate the dependent variables in a circuit with varying resistance?

To calculate the dependent variables, such as voltage and current, in a circuit with varying resistance, we can use Ohm's Law. By knowing the values of resistance, voltage, and current in the circuit, we can use the formula V=IR to solve for the dependent variable.

How can we manipulate the resistance in a circuit to achieve a desired outcome?

We can manipulate the resistance in a circuit by adding or removing resistors, changing the length or thickness of the wire, or using materials with different resistivity. By doing so, we can adjust the flow of current and voltage to achieve a desired outcome, such as controlling the brightness of a light bulb or the speed of a motor.

Back
Top