The discussion revolves around a problem involving circular motion, specifically analyzing the forces acting on a slider positioned on an inclined rod that rotates about a vertical axis. The problem includes elements of static friction, angular speed, and the dynamics of the slider's motion.
The conversation is active, with participants raising questions about the definitions and components of forces in the context of circular motion. Some guidance has been offered regarding the relationship between the normal force and the forces acting on the slider, but no consensus has been reached on certain assumptions.
Participants express confusion regarding the application of force equations in different scenarios, particularly comparing the current problem to banked curves and the role of static friction in maintaining the slider's position.
Of course it's not right, as I've been saying since my first post. Why do you think it's right? (For my reasons, reread this thread.)Latios1314 said:But back to the case of the inclined rod, can i say that
nsin60=mg?
Tried it. But the answer wasn't right. Could you tell me why?
It's very similar.Latios1314 said:But how is it different from a car on a banked road?
It does. You are confusing ncosθ = mg with n = mgcosθ. Big difference!but why doesn't a component of the normal force=mg here?
Because there is friction. To get an equation for the vertical forces you must include all vertical force components. Friction will have a vertical component.Latios1314 said:i mean for the case of a car on a banked road.
ncosθ = mg
But why doesn't nsinθ = mg for the case of the slider?