The discussion focuses on the dynamics of a slider on an inclined rod rotating with a constant angular speed, specifically analyzing the effects of static friction with a coefficient of u=0.2. Key calculations include the acceleration of the slider, determined to be 0.52w², and the maximum angular speed before slipping occurs, calculated as 4.07 rad/s. Additionally, the tangential contact force exerted by the rod on the slider when the angular speed increases at 10 rad/s² is found to be 5.2 N. The conversation emphasizes the importance of understanding the forces acting on the slider, particularly the role of normal and frictional forces in circular motion.
PREREQUISITESStudents and educators in physics, particularly those focusing on mechanics, as well as engineers and professionals involved in designing systems that incorporate rotational motion and frictional dynamics.
Of course it's not right, as I've been saying since my first post. Why do you think it's right? (For my reasons, reread this thread.)Latios1314 said:But back to the case of the inclined rod, can i say that
nsin60=mg?
Tried it. But the answer wasn't right. Could you tell me why?
It's very similar.Latios1314 said:But how is it different from a car on a banked road?
It does. You are confusing ncosθ = mg with n = mgcosθ. Big difference!but why doesn't a component of the normal force=mg here?
Because there is friction. To get an equation for the vertical forces you must include all vertical force components. Friction will have a vertical component.Latios1314 said:i mean for the case of a car on a banked road.
ncosθ = mg
But why doesn't nsinθ = mg for the case of the slider?