Circular Motion Concepts: Understanding the Stability of Rotating Objects

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SUMMARY

The discussion centers on the stability of a stone attached to a string when swung in a circular motion along the xy-axis, despite the gravitational force acting in the z-axis. Key insights include the necessity of maintaining an angle while swinging the string to create a balance of forces, specifically tension (T) and gravitational force (mg). A free-body diagram illustrates that the centripetal force generated by the stone's orbit counteracts gravity, allowing the stone to remain stable in motion. The displacement of the stone along the z-axis is a critical factor in this dynamic.

PREREQUISITES
  • Understanding of centripetal force and its role in circular motion
  • Familiarity with free-body diagrams and force resolution
  • Basic knowledge of gravitational force (mg) and tension (T) in strings
  • Concept of angular displacement in three-dimensional motion
NEXT STEPS
  • Study the principles of centripetal acceleration in circular motion
  • Learn how to construct and interpret free-body diagrams for dynamic systems
  • Explore the effects of angular displacement on the stability of rotating objects
  • Investigate the relationship between tension in strings and gravitational forces in circular motion
USEFUL FOR

Physics students, educators, and anyone interested in the mechanics of circular motion and the forces acting on rotating objects.

madah12
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Homework Statement


how come that if I grab a stone and attach it to a string and then rotate it along the xy axis it won't fall even though there is acceleration from gravity in the z axis where no force is applied?


Homework Equations





The Attempt at a Solution


maybe its the fact that I am holding the string comes to play I don't know.
 
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Notice that if you perform such an experiment, you'll need to swing the string at an angle constantly. If your own hand is in a x-y motion, yes the stone would drop. But if you want to swing the stone above your hand, what you're actually doing is swinging with a x-y-z component force.

If you draw a free-body diagram, there should be mg acting on the stone, tension of string, T, and the swinging force provided by the hand that is in the opposite direction of the tension. After all forces resolve, there should be the centripetal force only.
 
Last edited:
The stone isn't in the same xy plane as the point where you're holding it. It's somewhat lower, displaced along the z axis. The harder you swing the stone, the less that displacement will be, but it will never be zero. There will always be a component which, when multiplied against the centripetal force generated by the orbiting stone, will be enough to counteract the force of gravity on the stone.
 

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