Circular Motion Homework: Angular Velocity, Acceleration, Force Calculation

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SUMMARY

The discussion focuses on calculating angular velocity, acceleration, and force for a particle on a grinding wheel with a diameter of 0.12 cm spinning at 1200 RPM. The angular velocity was determined to be 2400π rad/s, with an acceleration of 14.4π m/s² and a force of 1.44 x 10⁻³π N acting on the particle. The radial force required to keep the particle on the wheel is 2.5 N, leading to a critical angular velocity of approximately 2041.241 rad/s, beyond which the particle will leave the wheel. The speed of the particle upon leaving the wheel is calculated to be 12.247 m/s, with its direction being tangential to the point of departure.

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Homework Statement


A grinding wheel has a diameter of 0.12 cm and spins horizontally at 1200 revolutions per minute about a vertical axis. A particle of mass 1 x 10-4 kg sticks to the wheel.

a. calculate the magnitude of the angular velocity, acceleration and force acting on the particle

b. the radial force that keeps the particle on the wheel is 2.5 N. calculate the angular velocity at which the particle leave the wheel.

c. if the wheel exceeds the angular speed in (b), calculate the speed and direction of motion of the particle just after it leaves the surface of the wheel.

Homework Equations


circular motion

The Attempt at a Solution


a.

\omega = 2\pi f = 2400\pi rad/s

a=\omega ^2 r = 14.4 \pi ms^2

F = ma = 1.44 x 10^{-3} \pi Nb.

F=m \omega ^2r

\omega ^2=\frac{2.5}{mr}

\omega= 2041.241 ~rad/sc.

v=\omega r=12.247 ms^{-1}

Direction of motion : tangential to the point where it leavesDo I get it right?

Thanks
 
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Assuming the particle is sticked to the very edge of the disk.

a) Check you angular velocity. the units is rad/s. and unit for the frequency is rev/min
 
Hi estalas

Aah my bad, forgot to change the unit. how about (b) and (c)? Are they correct?

Thanks
 

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