Circular Motion of bicycle wheel

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SUMMARY

The discussion focuses on calculating the ratio of forces acting on two rocks attached to a bicycle wheel with a radius of 0.5 m, completing one full turn in 1.6 seconds. The relevant equations include F=ma, F=mw²r, and F=(mv²)/r. The angular velocity was determined to be 3.9 m/s using the formula w=2πf. Participants emphasized the importance of deriving the force equations for each rock separately to identify canceling variables when calculating the force ratio.

PREREQUISITES
  • Understanding of circular motion and angular velocity
  • Familiarity with the equations of motion: F=ma, F=mw²r, and F=(mv²)/r
  • Basic knowledge of trigonometry for angular calculations
  • Ability to manipulate algebraic expressions to simplify equations
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  • Study the derivation of angular velocity and its applications in circular motion
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  • Explore the concept of centripetal force and its calculation
  • Investigate the implications of mass in force calculations and ratios
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Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators seeking to clarify concepts related to forces in rotational systems.

Asher242

Homework Statement


A bicycle wheel has a radius of 0.5 m. When it spins, it completes one full turn in 1.6 s. Two identical rocks are stuck on the wheel at a radius of 0.4 m and 0.2 m. What is the ratio of the force on the outer rock to that of the inner rock?

Homework Equations


F=ma
F=mw^2r
F= (mv^2)/r
These are the only formula's I believe could be relevant

The Attempt at a Solution


I've looked at both f=(mv^2)/r and f=mw^2r but I just can't get it. I don't understand how I'm supposed to find the force with on the time and the radius. This led me to believe that I don't have to necessarily solve it but after that I'm lost
 
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Asher242 said:

Homework Statement


A bicycle wheel has a radius of 0.5 m. When it spins, it completes one full turn in 1.6 s. Two identical rocks are stuck on the wheel at a radius of 0.4 m and 0.2 m. What is the ratio of the force on the outer rock to that of the inner rock?

Homework Equations


F=ma
F=mw^2r
F= (mv^2)/r
These are the only formula's I believe could be relevant

The Attempt at a Solution


I've looked at both f=(mv^2)/r and f=mw^2r but I just can't get it. I don't understand how I'm supposed to find the force with on the time and the radius. This led me to believe that I don't have to necessarily solve it but after that I'm lost
You need the angular speed, w. The wheel completes a full turn in 1.6 s. What angle is a full turn? What is the angular speed then?
 
Thank you so much for helping me :D

So going off of what you said I found the angular velocity to be 3.9ms (using w=2*pi*f) and from that I can also find the velocity of both of the rocks, however to find the force using either F=(mv^2)/r or F=mw^2r I would need the mass as there would be two unknown variables. Do I make up my own mass? (I've seen my teacher do it before) but, if everyone constructs their own mass it would be impossible to get the same answer right? Or, am I using the wrong formulas...
 
Asher242 said:
I found the angular velocity to be 3.9ms (using w=2*pi*f)
Your units are incorrect here.

But more importantly, pay attention to the bit of the question that requires you to find the ratio of two forces.

Write down the force equation for each rock separately, without plugging in any numbers. Just the symbols.
The question asks you to find ##F_1/F_2##. See if any variables cancel out.
 

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