On a Ferris Wheel A chemistry student with a mass of 75 kg is riding a steadily moving Ferris wheel. When she is at the top of the Ferris wheel, the normal force from the seat on to her body has a magnitude of 550 N. a) What is the magnitude of the normal force on her body when she is at the bottom of the Ferris wheel's arc? b.) What would the normal force be on the student at the top of the wheel if the wheel's velocity were doubled? FN =-7.25 F = (mv^2)/R Well I managed to solve for b by figuring out FN = 4(mg - 550) - 4(mg) = -7.25 But I'm really stuck on a. I don't understand why it just wouldn't be 550.