Circumcentre of an equilateral triangle

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Homework Help Overview

The discussion revolves around finding the distance from a vertex of an equilateral triangle to its circumcenter. The problem is situated within the context of geometry, specifically focusing on properties of triangles and circumcircles.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to determine the distance to the circumcenter and has calculated the distance from a vertex to the opposite side. Some participants suggest using geometric properties, such as the 30-60-90 triangle, to find the circumradius.

Discussion Status

Participants are exploring various approaches to the problem, including the use of the Pythagorean theorem and properties of special triangles. There is no explicit consensus on the best method, but some guidance has been offered regarding the use of geometric relationships.

Contextual Notes

There is a mention of a desire to solve the problem without using trigonometric functions, indicating a potential constraint or preference in the approach to the solution.

Chronos000
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1. Homework Statement [

what is the distance from one corner of an equilateral triangle of sides a to the circumcentre?


I can figure out the length from one corner to the opposite side to be sqrt3*a/2 but that's about it. I just can't see how to do this.

thanks
 
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Drop a perpendicular from the circumcenter to a side. That gives you a 30-60-90 triangle whose hypotenuse is the radius you are looking for.
 
thanks, the answer is a/sqrt3, I thought there was some way to do this without cos or sin but perhaps not
 
Chronos000 said:
thanks, the answer is a/sqrt3, I thought there was some way to do this without cos or sin but perhaps not

You could just use the pythagorean theorem if you really want to. If you call the circumcircle radius r, then the a*sqrt(3)/2 distance you computed minus r is the shorter leg of your 30-60-90 triangle. Now use the pythagorean theorem on it to solve for r. You don't really NEED the trig.
 

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