Circus attraction - How far does this sled move up an incline

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SUMMARY

The discussion focuses on calculating the distance a sled, carrying a monkey, moves up a 20-degree incline with an initial speed of 4 m/s. The total mass of the monkey and sled is 20 kg, and the coefficient of friction is 0.20. Key equations include potential energy (mgΔh), work of friction (force x distance), and kinetic energy (0.5mv²). The user attempts to derive an equation using energy principles, specifically considering the balance between gravitational potential energy and work done against friction.

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Homework Statement


In a circus performance, a monkey is strapped to a sled and both are given an initial speed of 4 m/s up a 20 degree inclined track. The combined mass of monkey and sled is 20 kg and the coefficient of friction between the sled and incline is .20. How far up the incline do the monkey and sled move?

Homework Equations


Potential energy gravity = mg(delta h)
Work of Friction = force x X
Kinetic energy = .5mv2
F perpendicular = fgcostheta
F parallel = fgsintheta

The Attempt at a Solution


I'm having the most trouble just coming up with the equation to use. As the monkey moves up he gains potential gravitational energy. He also loses some kinetic energy to the work of friction. I'm also not sure what to plug in for work of friction.
 
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its best to draw a force diagram before you go any farther.

draw a ramp inclined at 20 degrees, draw your force normal applied force and force of gravity. From that you should have an idea of where to start
 


I drew that and I came up with
f parallel - force friction = ma
I substituted and solved and got a=1.51 m/s
I'm not sure what to do from here. I know I could use kinematics to solve but I'm trying to do it using energy. Would the equation be Potential gravitational energy - work of friction = kinetic energy?
 

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