stevendaryl said:
I think we've been over this several times, already, but it seems to me that in a sequence of measurements of different properties, to get the right the answer, you have to describe the statement between measurements using something like the collapse hypothesis. In spin-1/2 twin-pair EPR, the system being measured is initially in the state \frac{1}{\sqrt{2}}(|U\rangle |D\rangle - |D\rangle |U\rangle). Alice measures her particle to have spin-up (along the z-axis). Then after her measurement, but before Bob's measurement, Bob's particle is in a state that is definitely spin-down along the z-axis. If you don't update the state of Bob's particle, you get the wrong answer.
No! That's only a claim, which is indistinguishable from the minimal interpretation. One must be a bit more precise. For Alice of course the situation changes and since she knows that she shares here photon with another one in the entangled pair, after her measurement she knows that Bob's particle will have for sure ##\sigma_z=-1/2##, but nothing has instantaneously changed at Bob's particle. Nevertheless the minimal interpretation gets the correct answer about the measurement statistics.
The only thing one knows for the experiment as a whole that the two particles have been prepared in the spin-singlet state ##|\psi \rangle=\sqrt{0.5} (|1/2,-1/2 \rangle-|-1/2,1/2 \rangle)## and that Alice and Bob have their SG apparatus directed in ##z## direction. Then you can ask for the probabilities that they find the four possibilities of outcomes ##(\sigma_1,\sigma_2)## with ##\sigma_j \in \{-1/2,+1/2 \}##. The four matrix elements obviously are
$$\langle 1/2,1/2 | \psi \rangle=\langle -1/2,-1/2|\psi \rangle=0, \quad \langle 1/2,-1/2 | \psi \rangle=-\langle -1/2,1/2|\psi \rangle=1/\sqrt{2},$$
i.e., you find with probility 1/2 either ##(1/2,-1/2)## or ##(-1/2,1/2)## but never ##(1/2,1/2)## or ##(-1/2,-1/2)##. That's just described by the initially prepared state. There's no need to change the state of B's particle due to A's measurement (*).
Of course from the point of view of A also everything is consistent. If A measures ##\sigma_z## of her particle, she'll find with probability 1/2 that ##\sigma_z=+1/2## and then knows that Bob will with certainty find ##\sigma_z=-1/2##, because there's no other possibility left. The outcome is the same as above, i.e., they measure ##(1/2,-1/2)## with probability 1/2 (and ##(-1/2,1/2)## also with probability 1/2), while it's not possible to find the same ##\sigma_z## for both particles.
So at the place of A you can invoke the "collapse hypothesis", but it's just about A's knowledge. Nothing happened instantaneously at B's place. The collapse is not "real". You don't make a mistake to apply it as a statement of A's knowledge about B's particle after having measured her particle's ##\sigma_z##, but it doesn't change anything concerning the outcome of the measurement and the statement about the physical meaning of the initially prepared spin-entangled two-particle state. So you can as well also forget about the collapse.
(*) Remark: The single-particle states of the two particles in the spin-entangled two-particle state is described by the reduced states, which are both
$$\hat{\rho}_A=\hat{\rho}_B = \frac{1}{2} \mathbb{1}.$$
For A and B they just find maximally unpolarized particles.
An alternative is to not deal with states at all, but to deal with possible histories of measurements. There is a probability \frac{1}{2} for the history in which Alice measures spin-up and Bob measures spin-down, and a probability of \frac{1}{2} that Alice measures spin-up and Bob measures spin-down. But dealing with histories instead of states is not standard QM, so I disagree that such an approach is "minimal", in the sense of taking standard QM without collapse.
Well, that's why I deal with the state, and nothing else. Envoking the collapse in the above very weak (not to say trivial sense) is more like this "history approach".