Classical Mechanics: 12N Block on Wall - Will it Move?

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Homework Help Overview

The discussion revolves around a classical mechanics problem involving a 1kg wooden block pressed against a wooden wall by a force of 12N. Participants are exploring whether the block will move or remain at rest, considering the effects of static friction and gravitational forces.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are analyzing the forces acting on the block, including gravitational force and static friction. There is a focus on the conditions under which the block might move or remain at rest, with some questioning the role of static friction in opposing motion.

Discussion Status

The discussion is active, with various interpretations being explored regarding the balance of forces. Some participants have offered insights into the maximum possible friction force and its implications for the block's motion, while others are questioning the assumptions made about the forces involved.

Contextual Notes

Participants note the coefficient of static friction for wood on wood as 0.50 and discuss the implications of this value in relation to the forces acting on the block. There is an acknowledgment that the maximum static friction could vary and that it plays a crucial role in determining the block's state of motion.

Bostonpancake0
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A 1kg wooden block is being pressed against a wooden wall by 12N. If the block is initially at rest will it move upward, downward or remain at rest?



Picture of problem is in link below along with my working out. co-effecient of static friction of wood on wood is 0.50. I have also made static friction and force upward in the y component positive (same direction) and fore of gravity downwards.
 

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answer in book says at rest
 
Bostonpancake0 said:
A 1kg wooden block is being pressed against a wooden wall by 12N. If the block is initially at rest will it move upward, downward or remain at rest?



Picture of problem is in link below along with my working out. co-effecient of static friction of wood on wood is 0.50. I have also made static friction and force upward in the y component positive (same direction) and fore of gravity downwards.

Don't forget that μR is the maximum available friction - it could always be less.

If the mass was to move up, friction would be acting down.

I would calculate what what happens in the absence of friction, then see if friction can prevent that happening.
 
in the absence of friction block moves down as Fg is greater than force of press in the vertical component. And i assumed that static frcition would play a role and oppose the direction of motion thus would act upwards (similar to that on an incline plane). so adding Fg, static friction and vertical upward force should give me a net force of zero right? if the object was to remain at rest, as stated in answers.
 
Bostonpancake0 said:
in the absence of friction block moves down as Fg is greater than force of press in the vertical component. And i assumed that static frcition would play a role and oppose the direction of motion thus would act upwards (similar to that on an incline plane). so adding Fg, static friction and vertical upward force should give me a net force of zero right? if the object was to remain at rest, as stated in answers.

Zero net force would be nice.

What size would the force of friction have to be to give a net force of zero?

What is the maximum size the friction force can be?

Does that mean it IS possible for friction to prevent motion?

Remember, friction will not drive the block in either direction, it can only prevent the block from moving.
 

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