Two cyclists, Anant and Beth, are standing on a straight road a distance d=22.0 m apart. Simultaneously, they begin to move toward each other, Anant with acceleration a_A=0.2 m/s^2 and Beth with acceleration a_b=0.10 m/s^2.
Just as they begin to move, a bee, sitting on Anant’s helmet, begins to fly toward Beth at a constant speed v=11.0m/s. Once the bee reaches Beth, it instantly turns around and flies back toward Anant. As the cyclists move toward each other, the bee continues to fly back-and-forth between the two until they pass each other. The speed of the bee remains constant.
How long does it take for the riders to pass each other?
What is the distance covered by the bee between the start and the moment Anant and Beth pass each other?
What is the average velocity of the bee between the start and the moment Anant and Beth pass each other?[/B]
x_0 for anant =0
x_0 for beth=22
The Attempt at a Solution
I found out the time it takes for them to cross each other.
therefore t=12.11060 seconds
I correctly found the distance covered by the bee
time* constant speed=12.11060*11=133.2166 m
but I trouble finding AVERAGE VELOCITY because I don't how to think about the DISPLACEMENT of the bee.