Classical Mechanics - finding displacement with given force

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Homework Help Overview

The discussion revolves around a classical mechanics problem involving the calculation of displacement for a particle subjected to a specific force equation. The force is defined in relation to the particle's position and velocity, and the initial conditions are provided.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss various methods for integrating the force equation and express uncertainty about the correct approach. Some question the validity of taking certain variables outside of integrals, while others explore changing variables to derive an implicit equation for position over time.

Discussion Status

The conversation is ongoing, with participants providing feedback on each other's attempts and clarifying misunderstandings about the integration process. There is no explicit consensus, but guidance has been offered regarding the treatment of variables in the integration.

Contextual Notes

Participants are navigating the complexities of integrating a force equation that involves both position and velocity, and there are indications of confusion regarding the treatment of these variables over time.

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Homework Statement


- The force acting on a particle m = 3kg is given by the following force equation: F = (v/9)(3 - x2),
the particle begins at a position of x = 1m with a speed of v = 0 m/s at time t = 0s. Find the displacement of the particle at time t = 5 s.

Homework Equations


F = m(dv/dt) or F= m(dv/dx)(v)

The Attempt at a Solution


Our professor set up the problem wrong, so he said all we have to do is get to the integral where we'd find x and stop.
 
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Welcome to PF;
... so what did you do?
 
Simon Bridge said:
Welcome to PF;
... so what did you do?
Well I tried it two ways, neither of which I thought was right...
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token=YcoBfb2774deTF3wZ6MaQrYbVQ%2fvPYwJAM%2faX8w795U%3d&docid=0155b644af83a49af8eeec1a8acd84697.jpg
 
In the first page, you cannot take the x's outside the integral over t because x is a function of time.
On the second page, you, instead, tried changing the variable ... that seems reasonable to me.
You'll end up with an implicit equation for x(t) but you only need x at a particular time.
 
Simon Bridge said:
In the first page, you cannot take the x's outside the integral over t because x is a function of time.
On the second page, you, instead, tried changing the variable ... that seems reasonable to me.
You'll end up with an implicit equation for x(t) but you only need x at a particular time.
So on the 2nd page you would end up with -(1/3)x3t + 3xt - (8/3)t ?
 
No - remember, the x terms are not constants in time.
You have to integrate the x terms wrt x.
 

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