1. The problem statement, all variables and given/known data a)Two people are holding the ends of a plank of length l and mass M. Show that, if one suddenly lets go, the initial acceleration of the free end (aD) is 3g/2. (7 marks). Moment of inertia, I, of the plank about its centre of mass is given by I=1/12(Ml2) b)Show also that the load supported by the other person falls from Mg/2 to Mg/4. (3 Marks). 2. Relevant equations I*angular acceleration=torque=rxF parallel axis theorem for the moment of inertia 3. The attempt at a solution I have completed the first 7 marks with no difficulty but am really struggling with how to set part b) up and what assumptions I need to make. I've spent hours and hours on this and have ended up going round in circles. I think I may need to calculate the linear acceleration of the centre of the plank and from this deduce the new load on the other hand. However I have not made much progress with this part of the question.