Classify fixed points non homogeneous system of linear differential equations

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SUMMARY

The discussion focuses on classifying fixed points in a non-homogeneous system of linear differential equations represented by the equations \(\dot{x}=2x+5y+1\) and \(\dot{y}=-x+3y-4\). The solution involves transforming the system into a homogeneous form by solving the associated equations \(2x + 5y = -1\) and \(-x + 3y = 4\) to find fixed points. A coordinate transformation is then applied, where \(x^* = x + x_0\) and \(y^* = y + y_0\), allowing the analysis of the fixed points in the new coordinate system. This method effectively simplifies the classification of fixed points in the original non-homogeneous system.

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Homework Statement



[tex]\dot{x}=2x+5y+1, \dot{y}=-x+3y-4[/tex]

Homework Equations




The Attempt at a Solution


Well, if system was: [tex]\dot{x}=2x+5y, \dot{y}=-x+3y[/tex] we let a=2, b=5, c=-1, d=3.
Then p = a + d and q =ad - bc and we investigate [tex]p^2-4q[/tex]
Don't know what to do when [tex]\dot{x}=2x+5y+1, \dot{y}=-x+3y-4[/tex]
Thanks
 
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Why don't you try making a change in coordinates?

Solve the system of equations:
[tex]2x + 5y = -1; -x + 3y = 4;[/tex]
for x and y. Assume we obtain the solutions [itex]x=x_0, y=y_0[/itex]. Then a substitution of the form [itex]x^* = x + x_0; y^* = y + y_0[/itex] will give you a set of homogeneous ODEs in a shifted coordinate system. Fixed points of this new set of ODEs are related to the old set by the coordinate transformations above.
 
good intelligent answer thank you
 

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