Closed-form expressions for FIR least squares inverse filters

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Homework Help Overview

The assignment involves finding closed-form expressions for the FIR least squares inverse filter of length N for specific transfer functions. The transfer functions provided include a first-order recursive filter and others that involve different forms of feedback and feedforward components.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the meaning of "closed-form" and the requirements for expressing the inverse of the given transfer functions. There is an attempt to clarify the misunderstanding regarding the nature of the expressions needed.

Discussion Status

Some participants have provided attempts at solutions, while others are questioning the interpretations of the problem and the definitions involved. There is an acknowledgment of misunderstanding, particularly regarding the steps necessary to find the inverse of the transfer functions.

Contextual Notes

Participants note that the assignment may involve specific constraints on the forms of the functions and the requirement to avoid recursive definitions or integrals in the closed-form expressions.

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Homework Statement



The assignment is to find a closed-form expression for the FIR least squares inverse filter of length N for each of the following systens

Homework Equations



$$
1.G( z ) = \frac{1}{1 - \alpha z^{-1}}; | \alpha | < 1 \\
2. G(z) = 1 - z^{-1} \\
3. G(z) = \frac{\alpha - z^{-1}}{1 - \alpha z^{-1}}; |\alpha| < 1
$$

The Attempt at a Solution

Anybody have any ideas, I can't really understand what is meant by close-form either from the book or from wikipedia. My guess is:
$$
1. G( z ) = \frac{z}{z - \alpha} \\
2. G( z ) = z-1 \\
3. G( z ) = \frac{z - 1 }{z - \alpha}
$$
Every helping hand is welcome
 
Last edited:
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Linder88 said:
FIR least squares inverse filter of length N
Your attempted solution does not seem to bear any relationship to that clause. Not an area I know anything about, but it is clear that you are not merely being asked to present G(z) in a closed form (those expressions already are).
Linder88 said:
what is meant by close-form
Closed form means an equation of the form function = (some combination of standard functions).
That is, the right hand side cannot contain any references back to the function being expressed, nor integrals, nor sums, nor any special functions defined for the purpose. There are some grey areas.
 
Yes, you are right. I realized that I have misunderstood the quetion, I'm supposed to first tale the inverse of $G(z)$
$$
1. G^{-1}(z)=\frac{1}{G(z)}=1-\alpha z^{-1} \\
2. G^{-1}(z)=\frac{1}{1-z^{-1}} \\
3. G^{-1}(z)=\frac{1-\alpha z^{-1}}{\alpha-z^{-1}}
$$
Now, I only need to make the inverse z-transform
$$
1. g(n) = -\alpha \delta(n-1) \\
2. g(n) = -u(n-1) \\
3.
$$
I'm not sure about the third
 
Last edited:
Linder88 said:
I'm not sure about the third
Expand as constant+constant/(α-z-1)?
 

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