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Closed integration of exact form

  1. Jun 10, 2014 #1
    If ##\omega## is an exact form ##( \omega = d\eta )## and ##\Omega## is the region of integration and ##\partial \Omega## represents the boundary of integration, so the following equation is correct:
    $$\\ \oint_{\partial \Omega} \omega = 0$$?
     
  2. jcsd
  3. Jun 10, 2014 #2

    Matterwave

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    By Stoke's theorem:

    $$\oint_{\partial\Omega} \omega =\int_{\Omega} d\omega=\int_{\Omega} dd\eta=0$$
     
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