Closed integration of exact form

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 4K views
Jhenrique
Messages
676
Reaction score
4
If ##\omega## is an exact form ##( \omega = d\eta )## and ##\Omega## is the region of integration and ##\partial \Omega## represents the boundary of integration, so the following equation is correct:
$$\\ \oint_{\partial \Omega} \omega = 0$$?
 
Physics news on Phys.org
By Stoke's theorem:

$$\oint_{\partial\Omega} \omega =\int_{\Omega} d\omega=\int_{\Omega} dd\eta=0$$
 
  • Like
Likes   Reactions: 1 person