Closed subspace of a Sobolev Space

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The discussion revolves around proving that the space \tilde{W}^{1,2}(\Omega), consisting of functions in W^{1,2}(\Omega) with an average value of 0, is a closed subspace. It is established that \tilde{W}^{1,2}(\Omega) is indeed a subspace of W^{1,2}(\Omega). The main challenge lies in demonstrating that the limit of a convergent sequence of functions from \tilde{W}^{1,2}(\Omega) also has an average value of 0. Suggestions are sought for how to approach this proof, particularly considering the boundedness of the sequence. The conclusion remains that further insights are needed to solidify the argument for closure.
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Homework Statement



I am considering the space \tilde{W}^{1,2}(\Omega) to be the class of functions in W^{1,2}(\Omega) satisfying the property that its average value on \Omega is 0. I would like to show that \tilde{W}^{1,2}(\Omega) is a closed subspace of W^{1,2}(\Omega).

Homework Equations


W^{1,2}(\Omega) is the space of L^2(\Omega) so that their distributional derivative also lie in L^2(\Omega).


The Attempt at a Solution



It is clear that \tilde{W}^{1,2}(\Omega) is a subspace of {W}^{1,2}(\Omega). So I now consider a convergent sequence of functions \tilde{w}_k in \tilde{W}^{1,2}(\Omega) converging to a function w in W^{1,2}(\Omega). I am having trouble showing that w has average value 0 and hence belongs in \tilde{W}^{1,2}(\Omega). Any suggestions.
 
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I am having a hard time making this conclusion. How about if the sequence is bounded?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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