If the coefficient of static friction for a 5.0 kg rubber block on a floor is 0.72, how much force is needed to start it sliding?
Co-efficient of Static Friction=0.72
coefficient of static friction = Friction Force/Surface Normal Force (equal to the weight of the object)
The Attempt at a Solution
Therefore, an applied force of at least 35 Newtons is needed to overcome the Friction Force and start the object moving. But the answer in the book gave me 106 Newtons. I don't know how that was arrived at...but strangely enough 35 * 3 = 106.
Thanks in advance for clearing up the matter for me.