Hello, please help me out on this:(adsbygoogle = window.adsbygoogle || []).push({});

Two equall masses lie on each side of a rough wedge, connected by a string, the wedge makes anlges 53, and 47, to the horizontal, find the coefficient of friction for the masses to move at a constant speed.

MY THINKING:

since masses are equal:

mgsin(53) = mgcos(53)(u) + mgcos(47)(U) + mgsin(47) ---> these are all the opposing forces, and force of fricton of each mass, since the slop is different for them.

the mg(s) cancels out. Leaving:

sin(53)-sin(47) = (cos53+cos47)(u)

then i got u = 0.052

which is wrong...

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# Homework Help: Coefficient of Friction at constant speed

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