Boy Exerts Force on 6kg Chair to Prevent Slipping

In summary, the friction force opposing the motion is equal to the coefficient of friction multiplied by the total downward force, which is the weight of the box (6g N) plus the force applied by the boy (F). Since the box is on the point of slipping but remains at rest, the friction force must be equal to the applied force of 25N. Therefore, we can solve the equation 0.35(6g+ F)= 25 for F to find the force that the boy exerts on the chair.
  • #1
Shah 72
MHB
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A chair of mass 6kg is at rest on a rough horizontal floor with coefficient of friction 0.35. It is pulled horizontally by a force of 25N. A boy pushes down on the chair so that the chair is on the point of slipping but remains at rest. Find the force that the boy exerts on the chair.
 
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  • #2
The friction force, opposing the motion, is the coefficient of friction times the downward force In this case the downward force is the weight of the box, 6g N (g is the acceleration due to gravity, 9.81 meters per second squared), plus the downward force applied by the boy, Calling that force, F, that is a total downward force, 6g+ F Newtons so the friction force is 0.35(6g+ F) Newtons. Since the box " is on the point of slipping but remains at rest" that must be equal to the applied force 25 Newtons.

Solve 0.35(6g+ F)= 25 for F.
 
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  • #3
Country Boy said:
The friction force, opposing the motion, is the coefficient of friction times the downward force In this case the downward force is the weight of the box, 6g N (g is the acceleration due to gravity, 9.81 meters per second squared), plus the downward force applied by the boy, Calling that force, F, that is a total downward force, 6g+ F Newtons so the friction force is 0.35(6g+ F) Newtons. Since the box " is on the point of slipping but remains at rest" that must be equal to the applied force 25 Newtons.

Solve 0.35(6g+ F)= 25 for F.
Thank you so much!
 

FAQ: Boy Exerts Force on 6kg Chair to Prevent Slipping

1. What is the purpose of the experiment?

The purpose of the experiment is to determine the amount of force exerted by a boy on a 6kg chair to prevent it from slipping. This can help us understand the concept of friction and how it affects the motion of objects.

2. What materials are needed for the experiment?

The materials needed for the experiment include a 6kg chair, a force meter, and a boy who can exert force on the chair. Optional materials may include a non-slip mat or surface to place the chair on.

3. How is the force exerted by the boy measured?

The force exerted by the boy is measured using a force meter, also known as a spring scale. This device measures the amount of force in Newtons by stretching a spring. The more force applied, the more the spring stretches and the higher the reading on the scale.

4. What factors can affect the amount of force needed to prevent the chair from slipping?

The amount of force needed to prevent the chair from slipping can be affected by factors such as the weight of the chair, the surface it is placed on, the friction between the chair and the surface, and the strength of the boy exerting the force.

5. What are the potential applications of this experiment?

This experiment can help us understand the concept of friction and how it affects the motion of objects. It can also be applied in real-life situations such as designing non-slip surfaces or calculating the force needed to prevent objects from slipping or sliding.

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