a block with a mass of 0.310kg at a constant velocity , calculate the coefficient of kinetic friction on an incline plane
fparallel= mg* sin30 degrees
The Attempt at a Solution
I found the FN which is 2.60 and the f parallel to be 1.52. i found force applied to be 2n as the block moved up the incline and the as the block moved downwards to be 1N which is a 1/2 of that. I understand that you have to calculate net force going up and down the incline then since they will be equal to one another, try to isolate μ.
which will give you something like μ= x tan 30 degree. however how do i find out what the x is?
Is the force applied = to the f parallel
This is what I did:
F1 (block moving up) = 2F2 (moving downward)
fnet (for box going upward): fparallel + F1 + Ff(mu*Fn)
Fnet (for box going downward) : F2- Ff+ Fparallel
Then i made them equal to each other since they have a constant velocity, then i subtracted one from the other to get f parallel (m*g*sin31) = mu* mg Cos31 ,
then by dividing the fparallel by the mu*m g cos31, i got
mu= tan 31 degrees..
Am i doing this right?