A 98 N box of oranges is being pushed across a horizontal clean steel surface until it stops. As it moves, it is slowing down at a constant rate of 1.1m/s each second. The push force has a horizontal component of 25N and a vertical component of 20N downward. Calculate the coefficient of kinetic friction between the box and the floor.
The Attempt at a Solution
summation of Fx = 25N - fk = ma
= 25N - fk = (10kg)(1.1m/s^2)
fk = 14N???
summation of Fy= 0 = -Fw - Fdown +normal force
normal force = 20N + 98N = 118N???
fk = (uk)(Fn)
(14N / 118N) = uk
uk = 0.119