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physlexic
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Homework Statement
Problem:
A 10 kg box slides down a hill and has a constant velocity. The angle of the hill is 10° with respect to the horizontal. What is the coefficient of kinetic friction between the surface of the hill and the box?
Homework Equations
Fn = mg + ma
ƒk = μk * Fn
The Attempt at a Solution
To calculate the coefficient of kinetic friction I used the formula ƒk = μk Fn and isolated μk to be
μk = ƒk / Fn
Where ƒk is kinetic frictional force, μk is the coefficient of kinetic friction, and Fn is the normal force.
I don't have any of these variables, so I drew a free-body diagram and tried to find my normal force by doing:
∑Fy = Fn + mg cos 10° = 0
Fn = mg cos 10°
Fn = (10 kg) (9.80 m/s^2) cos 10° = 96.5 NMy problem is I am not sure on how to determine my kinetic fricitonal force ƒk to plug it into the
μk = ƒk / Fn. Someone please guide me? [/B]