Coefficient of Kinetic Friction

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SUMMARY

The coefficient of kinetic friction between a crate of bananas and the floor was calculated using the initial speed of 4.2 m/s and a stopping distance of 6.0 m. The acceleration was determined to be 1.47 m/s², leading to a final coefficient of kinetic friction value of 0.15. This calculation was confirmed by the forum participants, establishing the accuracy of the method used.

PREREQUISITES
  • Understanding of Newton's second law (Fnet=ma)
  • Knowledge of kinematic equations, specifically v² = v₀² + 2aΔx
  • Basic algebra for solving equations
  • Familiarity with the concept of friction and its coefficients
NEXT STEPS
  • Study the derivation of the coefficient of kinetic friction in different scenarios
  • Learn about the effects of surface materials on friction coefficients
  • Explore advanced kinematic equations for varying acceleration
  • Investigate real-world applications of friction in engineering
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Students in physics, mechanical engineers, and anyone interested in understanding the principles of motion and friction in practical applications.

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Homework Statement



A crate of bananas has an initial speed of 4.2 m/s2. It slides across a floor, traveling 6.0m before coming to a stop. Find the coefficient of kinetic friction between the crate and the floor.

Homework Equations


Fnet=ma
v2=v02+2aΔx



The Attempt at a Solution



v=4.2 m/s
x=6.0 m
vf=0
Δx=6.0 m

a=v2-v02/2x
a=0-17.64 m/s2/12 m = 1.47m/s2
[itex]M[/itex]N=ma
mg=a
mg=a/g
m=1.47 m/s2/9.8m/s2=.15

For a final answer of .15. This seems correct to me, but could someone please confirm?

Sorry about the doubled template, I don't know how to get rid of it without messing up my post! Any ideas? :smile:


 
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