Coefficient of performance of refrigerator

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SUMMARY

The discussion focuses on calculating the coefficient of performance (K) for a refrigerator operating with 0.850 mol of hydrogen gas, treated as an ideal gas. The correct formula for K is established as K = QC/|QH - QC|, where QC is derived from isothermal and constant volume processes. The user initially calculated K as 0.462 but later corrected it to 6.23 after clarifying the signs of QH and QC. The importance of correctly identifying the signs of heat transfer in thermodynamic equations is emphasized.

PREREQUISITES
  • Understanding of ideal gas laws and equations (pV = nRT).
  • Knowledge of thermodynamic processes, specifically isothermal and constant volume processes.
  • Familiarity with the concept of coefficient of performance in refrigeration cycles.
  • Basic calculus for evaluating integrals in thermodynamic equations.
NEXT STEPS
  • Study the derivation of the coefficient of performance for different refrigeration cycles.
  • Learn about the implications of heat transfer signs in thermodynamic calculations.
  • Explore the application of the ideal gas law in real-world refrigeration systems.
  • Investigate the differences between isothermal and adiabatic processes in thermodynamics.
USEFUL FOR

Students in thermodynamics, engineers working on refrigeration systems, and anyone involved in the study of heat transfer and energy efficiency in mechanical systems.

Elias Waranoi
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Homework Statement


The pV-diagram in Fig. P20.51 (See attached file) shows the cycle for a refrigerator operating on 0.850 mol of H2. Assume that the gas can be treated as ideal. Process ab is isothermal. Find the coefficient of performance of this refrigerator.

Homework Equations


K = QC/|QH - QC|
pV = nRT
Cp = Cv + R
Isothermal expansion: Q = W = ∫p dV = nRT*ln(V2/V1)
Constant volume: Q = nCvΔT
Constant pressure: Q = nCpΔT

The Attempt at a Solution


QC = Qa-b + Qb-c = nRTa * ln(Vb/Va) + nCv(Tc - Tb) = paVa * ln(Vb/Va) + VbCv(pc - paVa/Vb)

QH = Qc-a = n(Cv + R)(Ta - Tc) = pc(Cv + R)(Va - Vc)/R

My answer K = QC/|QH - QC| = 0.462
Correct answer K = 6.23

What did I do wrong?
 

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Elias Waranoi said:
QC = Qa-b + Qb-c = nRTa * ln(Vb/Va) + nCv(Tc - Tb) = paVa * ln(Vb/Va) + VbCv(pc - paVa/Vb)
Did you leave out R somewhere in the last term on the right side?

QH = Qc-a = n(Cv + R)(Ta - Tc) = pc(Cv + R)(Va - Vc)/R
Does this give a positive or negative value for QH? In the formula K = QC/|QH - QC|, is QH considered as positive or negative?
 
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QC = paVa * ln(Vb/Va) + VbCv(pc - paVa/Vb)/R

QH is heat the leaves the working substance so it should be negative. Apparently K = |QC|/( |QH| - |QC| ), thanks for the help I got the correct answer now.
 

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