Carnot Refrigerator Efficiency and Energy Calculations | Homework Help

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SUMMARY

The discussion focuses on calculating the efficiency and energy requirements of an ideal Carnot refrigerator operating between 0°C and 25°C. To convert 10 kg of water at 0°C into ice at the same temperature, participants explore the heat exhausted into the room and the energy supplied to the refrigerator. Key formulas include the coefficient of performance (COP) defined as Kcarnot = Tc/(Th - Tc) and the relationship W = Qh - Qc. The conversation emphasizes the importance of understanding the Carnot cycle's reversible nature in determining work and efficiency.

PREREQUISITES
  • Understanding of the Carnot cycle and its principles
  • Familiarity with thermodynamic concepts such as heat transfer and work
  • Knowledge of the coefficient of performance (COP) for refrigerators
  • Basic proficiency in algebra for manipulating thermodynamic equations
NEXT STEPS
  • Study the derivation of the Carnot cycle efficiency formulas
  • Learn how to calculate heat transfer in refrigeration processes
  • Explore real-world applications of the Carnot cycle in modern refrigeration systems
  • Investigate the impact of temperature differences on refrigerator performance
USEFUL FOR

Students in thermodynamics, engineers working with refrigeration systems, and anyone interested in optimizing energy efficiency in cooling applications.

lindsey4
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Homework Statement


An ideal refrigerator utilizes a carnot cycle operating between 0 and 25 degrees celsius. To turn 10 kg of water at 0 degrees celsius into 10 kg of ice at 0 degrees celsius,
a) how much heat is exhausted into the room?
b) how much energy must be supplied to the refrigerator?

Homework Equations



coefficient of performance of carnot refrigerator (Kcarnot): Tc/(Th-Tc)
n (funky n for efficiency thing)=Wout/Qh [but isn't that for engine]
K=Qc/W

The Attempt at a Solution



I'm guessing part A is Q so I'd have to find that somehow. And, for part B I think you use the last formula I put here and input Q to find W.
 
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lindsey4 said:
coefficient of performance of carnot refrigerator (Kcarnot): Tc/(Th-Tc)
n (funky n for efficiency thing)=Wout/Qh [but isn't that for engine]
An ideal Carnot cycle is reversible, so W is the work, whether it's in or out.
The only thing that changes is how efficiency is defined. Equations not involving η are unchanged.
W = QH (1-TC/TH ) = QC (1-TH/TC )
I'm guessing part A is Q so I'd have to find that somehow.
There are two Qs: QH and QC. Which do you want for part A?
 
lindsey4 said:

Homework Statement


An ideal refrigerator utilizes a carnot cycle operating between 0 and 25 degrees celsius. To turn 10 kg of water at 0 degrees celsius into 10 kg of ice at 0 degrees celsius,
a) how much heat is exhausted into the room?
b) how much energy must be supplied to the refrigerator?

Homework Equations



coefficient of performance of carnot refrigerator (Kcarnot): Tc/(Th-Tc)
n (funky n for efficiency thing)=Wout/Qh [but isn't that for engine]
K=Qc/W
The COP for the refrigerator is output/input where the output is the amount of heat removed from the cold reservoir, Qc and W is the work supplied: COP = Qc/W

Since W = Qh-Qc, and Th/Tc = Qh/Qc, you can express COP in terms of Th and Tc (your expression is correct).

For a) what do you need to find? (hint: it is one of W, Qh or Qc). For b) what do you need to find? (same hint)

AM
 
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