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B Coefficient of Restitution in x and y

  1. May 28, 2017 #1
    I am currently studying collisions in high school and my teacher told us that, in order to calculate the direction of each object after a 2-body collision, we could change the values in the relative velocity terms of the equation of the coefficient of restitution to the components in x and y. Is this true? Thanks.
     
  2. jcsd
  3. May 29, 2017 #2

    Ssnow

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    If collisions are on a line, you can fix a positive orientation of the line so you have positive and negative velocities respect the two opposit directions... it is possible to interpret the minus in front of the vector as a velocity in the opposite sense ...
    If the collision is in the plane you can always do the same component by component ....
    I don't know if I answered ...
    Ssnow
     
  4. May 29, 2017 #3
    So, say, if one of the bodies moves along the x axis, and the other moves with an angle of 120 with respect to the horizontal, one can write ##e_x = (v_2cos(120) - v_1)/(u_1 - u_2cos(120)## ?
     
  5. May 29, 2017 #4

    Ssnow

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    mmmmh, what is ##e_{x}## ? ...... if the ##\vec{v}=(v_{1},v_{2})## is the first vector and ##\vec{u}=(u_{1},u_{2})## the second forming an angle of ##120°## then ##\vec{v}=(v_{1},0)## because is on the ##x## axis and ##\vec{u}=(u\cos{(120)},u\sin{(120)})## where ##u## is the magnitude of ##\vec{u}##. Now you must fix a sign ##\pm## to each component that describes the collision ...
    Ssnow
     
  6. May 29, 2017 #5
    I meant ##e_x## to be the coefficient of restitution. Sorry for not specifying. Anyways, I get it now. Thanks
     
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