Coefficients of kinetic friction, help PLEASE

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Homework Help Overview

The problem involves a hockey puck sliding on ice, with initial and final speeds provided over a time interval. Participants are exploring the concepts of average acceleration and the coefficient of kinetic friction.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the application of Newton's second law and the definition of kinetic friction. There is a focus on how to relate acceleration to friction without having the mass of the puck.

Discussion Status

The discussion has progressed with some participants providing guidance on relating forces to acceleration. One participant initially expresses confusion about the lack of mass but later indicates they found a way to derive the coefficient of kinetic friction.

Contextual Notes

Participants note the absence of mass as a constraint in solving part B of the problem, which leads to questions about how to proceed with the calculations.

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Here is the problem:

A hockey puck is hit on a frozen lake and starts moving with a speed of 13.0 m/s. Five seconds later, its speed is 5.20 m/s.

(a) What is its average acceleration?

I used the kinematic equation V=Vo+at to find the accerlation which came out to be -1.56 m/s^2 (this answer is right).

(b) What is the average value of the coefficient of kinetic friction between puck and ice?

(c) How far does the puck travel during the 5.00 s interval? m

I used X-Xo=1/2[V+Vo]t to solve this and got 45.5 m, which is right.


So basically, I'm stuck on part B of this problem. I don't remember my professor going over how to solve this particular type of problem in class so I was hoping someone here could get me started. I'm not asking for the answer, just an explanation of how to solve Part B.
 
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Think about forces and Newton's second law. You have already figured out the acceleration. What's the definition of kinetic friction?
 
I assume I would make F=ma equal to Fk=uN.

However, I don't see how I can do this since the mass wasn't given.
 
OK, but what is the normal force equal to?
 
The normal force is equal to the weight, which is mass x gravity, but again I get lost because I don't have the mass.
 
Wait, nevermind. I got it. I divided acceleration/gravity and came out with the answer.

Thanks for your help though!
 
Good!

You're welcome :smile:
 

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