Hanshananigan
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I saw this thread at the top of a Google search, so I thought it might be worth an illustration of why the OP's logic doesn't hold up.
I used Excel to create 104 sets of 400 "coin flips." By the OP's logic, if the first 200 flips in each set tended to be more heads or more tails, the second 200 flips should have "pressure" to reverse that trend to result in a closer to 50/50 split. Ignoring the few sets that had 100 "heads" in the first 200 flips (50/50 split, so there would be no "pressure") and those that had 100 "heads" in the second 200 flips, I counted how many sets had >100 heads in the first 200 flips and <100 heads in the second 200 flips and did the same thing for tails (perhaps providing evidence of "pressure"), and calculated a rate of how many trials supported the "pressure" hypothesis (ignoring those trials with 100 "heads" in the first or second 200 flips). To keep things simple, I ran each set of trials 10 times and calculated the rate for each set.
It was expected that the rate of trials supporting the "pressure" hypothesis would be significantly > 50%.
The results: 56, 49, 53, 53, 48, 39, 45, 48, 52, 37
That is, an average 48% of the time, if #heads > #tails in the first 200 flips, that trend would be reversed in the second 200 flips. Thus, no evidence of "pressure."
In terms of application on the roulette table, if you have enough cash for 40 spins, and you know the outcomes of the first 20 tended to be "black," you will not necessarily come out ahead if you bet on "red" for the next 20 spins.
Looking at it another way, for those trials in which at least 110 flips of the first 200 were heads, the 201st flip was tails only an average of 45.1% (36, 40, 56, 60, 64, 44, 58, 67, 50, 40). Although 45% seems like a decent spread for betting, the variance across trials is huge due to the infrequency of finding at least 110 flips among 400 trials, so the confidence interval will be wide. Again, even if the roulette table has tended to run "black," it does not affect subsequent spins. Not worth betting on.
These outcomes will be expected by most of those who posted on this thread. For anyone else, I hope this example provides a link between the OP's logic and the properties of probability offered by others.
I used Excel to create 104 sets of 400 "coin flips." By the OP's logic, if the first 200 flips in each set tended to be more heads or more tails, the second 200 flips should have "pressure" to reverse that trend to result in a closer to 50/50 split. Ignoring the few sets that had 100 "heads" in the first 200 flips (50/50 split, so there would be no "pressure") and those that had 100 "heads" in the second 200 flips, I counted how many sets had >100 heads in the first 200 flips and <100 heads in the second 200 flips and did the same thing for tails (perhaps providing evidence of "pressure"), and calculated a rate of how many trials supported the "pressure" hypothesis (ignoring those trials with 100 "heads" in the first or second 200 flips). To keep things simple, I ran each set of trials 10 times and calculated the rate for each set.
It was expected that the rate of trials supporting the "pressure" hypothesis would be significantly > 50%.
The results: 56, 49, 53, 53, 48, 39, 45, 48, 52, 37
That is, an average 48% of the time, if #heads > #tails in the first 200 flips, that trend would be reversed in the second 200 flips. Thus, no evidence of "pressure."
In terms of application on the roulette table, if you have enough cash for 40 spins, and you know the outcomes of the first 20 tended to be "black," you will not necessarily come out ahead if you bet on "red" for the next 20 spins.
Looking at it another way, for those trials in which at least 110 flips of the first 200 were heads, the 201st flip was tails only an average of 45.1% (36, 40, 56, 60, 64, 44, 58, 67, 50, 40). Although 45% seems like a decent spread for betting, the variance across trials is huge due to the infrequency of finding at least 110 flips among 400 trials, so the confidence interval will be wide. Again, even if the roulette table has tended to run "black," it does not affect subsequent spins. Not worth betting on.
These outcomes will be expected by most of those who posted on this thread. For anyone else, I hope this example provides a link between the OP's logic and the properties of probability offered by others.
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