Collision angle of deflection problem

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SUMMARY

The discussion centers on solving a collision angle of deflection problem involving two masses, m1 and m2, where m1 collides with a stationary m2. The key to solving this problem lies in applying the law of conservation of momentum in both the x and y directions. By equating the total momentum before and after the collision using vector components, one can derive the angle of deflection for m2. The approach involves creating two equations based on momentum conservation and substituting variables to arrive at the desired formula.

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PhysicsDud
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I'm really stuck on this questions, I don't even know where to start, can anyone help me?

A particle of mass m1 and velocity v1 collides with a stationary mass m2. After the collision, the two masses are deflected as shown in the diagram. Show that the angle of deflection Angle2 of m2 is given by the formula:

See Attached for formula and diagram.

Thanks,

Physics DUD
 

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I can't see the diagram yet, but I guaratee you that you start with the law of conservqation of momentum.

Momentum is conserved in the x-direction, and momentum is conserved in the y-direction.

Write a statement equating the total x-momentum before with the total x-momentum after (using vector componants).

Write a second statement equating y-momentum before and after.

If you define the x-direction as the direction m1 is traveling, then the total y-momentum will be ... you know?
 
The way that you do that is simple. Look at the momentum of the mass in the vertical and horizontal components. You should get two equations, all you do then is substitute one into the other (replacing v2 in the process). This should get you the required result.
 

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