Collision in frictionless surface

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When a steady horizontal force P is applied to three numbered cubes of equal mass m on a frictionless surface, the force on each cube will be P/3. The acceleration of each cube is determined to be P/3m, confirming that the force is evenly distributed. It is established that if the masses are equal, the net forces acting on each cube must also be equal. In a frictionless scenario, the lack of friction ensures that the applied forces remain consistent across the cubes. This understanding clarifies the dynamics of force distribution in such systems.
Smileyxx
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Homework Statement




three numbered cubes each of mass m placed in contact on a frictionless horizontal surface. A steady horizontal force P is applied to the end surface of 1st cube.
question:will the force on each cube be P/3?
 
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Hi Smileyxx! :smile:
Smileyxx said:
question:will the force on each cube be P/3?

Hint: what is the acceleration of each cube? :wink:
 
Its P/3m so force is P/3.ohh ya! But is always the force distributed equal in frictionless surface?
 
Smileyxx said:
Its P/3m so force is P/3.ohh ya! But is always the force distributed equal in frictionless surface?

Yes, if the masses are equal, then the net forces must be the same.

So if the friction forces are equal (or all zero), then the applied forces must be the same. :smile:
 
tiny-tim said:
Yes, if the masses are equal, then the net forces must be the same.

So if the friction forces are equal (or all zero), then the applied forces must be the same. :smile:
Thanks a lot bro:wink:
 
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