Collision in frictionless surface

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Homework Help Overview

The problem involves three cubes of mass m placed on a frictionless surface, with a steady horizontal force P applied to the first cube. The main question raised is whether the force on each cube will be P/3.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the distribution of force among the cubes and question if the force is always equally distributed on a frictionless surface. They also consider the implications of equal mass on the net forces acting on the cubes.

Discussion Status

There is an ongoing exploration of the relationship between mass, force distribution, and acceleration. Some participants suggest that if the masses are equal, the net forces must also be equal, while others are questioning the generality of this assumption.

Contextual Notes

Participants are discussing the implications of the frictionless condition and the equal mass assumption, which may affect their conclusions about force distribution.

Smileyxx
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Homework Statement




three numbered cubes each of mass m placed in contact on a frictionless horizontal surface. A steady horizontal force P is applied to the end surface of 1st cube.
question:will the force on each cube be P/3?
 
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Hi Smileyxx! :smile:
Smileyxx said:
question:will the force on each cube be P/3?

Hint: what is the acceleration of each cube? :wink:
 
Its P/3m so force is P/3.ohh ya! But is always the force distributed equal in frictionless surface?
 
Smileyxx said:
Its P/3m so force is P/3.ohh ya! But is always the force distributed equal in frictionless surface?

Yes, if the masses are equal, then the net forces must be the same.

So if the friction forces are equal (or all zero), then the applied forces must be the same. :smile:
 
tiny-tim said:
Yes, if the masses are equal, then the net forces must be the same.

So if the friction forces are equal (or all zero), then the applied forces must be the same. :smile:
Thanks a lot bro:wink:
 

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