Collision of 2 balls of different masses traveling opposite direction

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SUMMARY

The discussion revolves around a collision problem involving two balls, A and B, with masses of 0.5 kg and 0.2 kg, respectively. Ball A travels at 3 m/s and ball B at 2 m/s before colliding. After the collision, ball A's speed is 1.5 m/s, and the speed of ball B is calculated to be 7.3 m/s using the conservation of momentum principle. The impulse exerted on ball B is determined to be 1.06 Ns, calculated using the formula Ft = mu - mv.

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_Mayday_
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Question

Two small balls A and B have masses 0.5kg and 0.2kg respectively. They are moving towards each other in opposited directions on a smooth horizontal table when they collide directly. Immediately before the collision, the spped of A is 3m/s and the speed of B is 2m/s. The speed of A immediately after the collision is 1.5m/s. The direction of the motion of A is unchanged as a result of the collision.

By modelling the balls as particles, find

(a) The speed of B immediately after the collision


(b) The magnitude of the impulse exerted on B after the collision

Equations

Ft=mv-mu

My Attempt

(a) Conservation of momentum would mean that the initial momentum must be equal to the final momentum.

Ft=mv-mu

(0.5\times3.0)-(0.2\times2.0)=(0.5\times1.5)-(0.2\times x)

1.1=0.75-(0.2\timesx)

x=11.3m/s

(b) I have no Idea where to start here, I think it's more a question of now knowing what it is asking for. Is it asking for my value for Ft?


Any help would be great :cool:
 
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You might want to check your arithmetic on question (a). Yes, (b) is just asking you for the impulse which is the quantity Ft.
 
Sorry let me do that

first bit again.

(a)

1.1=0.75-0.2x

1\frac{7}{15} = 0.26

x = 7.3m/s

I hope that's a bit better o:)

(b)

Ft=mu-mv

Ft=0.2\times2-0.2\times7.3 = 1.06Ns

Does that look a bit better?
 
_Mayday_ said:
Sorry let me do that

first bit again.

(a)

1.1=0.75-0.2x
Good :smile:
_Mayday_ said:
1\frac{7}{15} = 0.26
Not so good, where's your x gone?
_Mayday_ said:
x = 7.3m/s
Take a sanity check, does this seem reasonable to you?
 
Sorry let me do that

first bit again.

(a)

1.1=0.75-0.2x

\frac{1.1}{0.75} = 1\frac{7}{15} = 0.2x

x = \frac{1\frac{7}{15}}{0.2} = 7\frac{1}{3}

I would have thought th answer to be around 3.5 as that would make all the initial and final figures equal...
 
Your making your mistake between this step,
_Mayday_ said:
1.1=0.75-0.2x
And this one,
_Mayday_ said:
\frac{1.1}{0.75} = 1\frac{7}{15} = 0.2x
Let me show you step by step,

1.1=0.75-0.2x

1.1-0.75 = -0.2x

x = \frac{1.1-0.75}{-0.2}

Do you follow?
 
Oh my word! I can't believe I did that! Thats a shocker haha. Cheers I follow that, and now with that I will get the correct answer for (b) thanks =]
 
_Mayday_ said:
Cheers I follow that, and now with that I will get the correct answer for (b) thanks =]
A pleasure as always :smile:
 

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