Comapring acceleration of person in elevator

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SUMMARY

The discussion centers on the acceleration of two individuals in identical elevators, one standing normally and the other hanging from the ceiling. Both individuals have a mass of 70 kg, and the forces acting on them include weight, tension, and normal force. The conclusion drawn is that the acceleration experienced by both individuals is equal in magnitude and direction when the elevators move upwards, assuming they accelerate at the same rate. The phrase "identical elevators" implies that both elevators have the same mass and accelerate uniformly.

PREREQUISITES
  • Understanding of Newton's Second Law (F = m.a)
  • Knowledge of forces: weight, tension, and normal force
  • Basic principles of kinematics in vertical motion
  • Concept of acceleration in a gravitational field
NEXT STEPS
  • Study the implications of Newton's Second Law in different scenarios
  • Learn about tension and normal force in various contexts
  • Explore kinematic equations for objects in free fall and under acceleration
  • Investigate the effects of varying mass and acceleration on force calculations
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Physics students, educators, and anyone interested in understanding the dynamics of forces in motion, particularly in elevator systems.

songoku
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Homework Statement



Two persons, each having mass 70 kg, stand in identical elevators. One stand normally, one hangs in the ceiling of elevator. How is the acceleration of them when the elevators move?

a. Equal in magnitude and direction

b. Equal in magnitude and opposite in direction

c. Different in magnitude but equal in direction

d. Different in magnitude and direction

e. Not enough information

Homework Equations


F = m.a

The Attempt at a Solution


I assume the second person hangs on a rope attached to the ceiling of the elevator so there are two forces acting on the man, weight and tension. There are also two forces acting on the man who stands in the elevator, weight and normal force.

Assuming the elevators move upwards, the acceleration experienced by each man is:

a = (T - W) / m and a = (N - W)/m

We don't know the exact value of T and N, so the answer will be "not enough information"?

Thanks
 
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songoku said:
I assume the second person hangs on a rope attached to the ceiling of the elevator so there are two forces acting on the man, weight and tension. There are also two forces acting on the man who stands in the elevator, weight and normal force.

Assuming the elevators move upwards, the acceleration experienced by each man is:

a = (T - W) / m and a = (N - W)/m

We don't know the exact value of T and N, so the answer will be "not enough information"?
Who says?

T = W + ma

N = W + ma

T = N

Chet
 
Chestermiller said:
Who says?

T = W + ma

N = W + ma

T = N

Chet

T = N is only when the acceleration of the two elevators is the same. Does the phrase: "identical elevators" imply that those elevators will move with same acceleration or just imply that the elevators have the same mass?

Thanks
 
songoku said:
T = N is only when the acceleration of the two elevators is the same. Does the phrase: "identical elevators" imply that those elevators will move with same acceleration or just imply that the elevators have the same mass?

Thanks
It's open to interpretation. It doesn't really matter does it? The important thing is that you analyzed the situation correctly.

Chet
 
It is normal in such introductory problems to make simplifying assumptions such as "identical elevators" => elevators are accelerating at the same rate and in the same gravitational field. That is, the elevators are identical in all respects that are significant to the problem at hand.
 
OK. Thanks a lot for all the explanation
 

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