Common source amplifier low frequency resonse

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The discussion centers on the role of capacitor Cs in a common source amplifier's current divider. A participant seeks clarification on why Cs is not included in the current divider calculation, specifically how it influences the output current Io. After some confusion, the participant acknowledges understanding the concept better. The conversation concludes with no further questions about the amplifier. The importance of understanding the interaction between Cs and the current divider is emphasized.
TheRedDevil18
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Here's the amplifier in question:
common source.PNG


I'm not understanding this part:
answer.PNG


Why is Cs not included in the current divider ?
To my understanding of current divider, It = Id+Io, where It is the current flowing through Rd
So, Io = It*(1/Cs)/(1/Cc2)+RL
 
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But Cs is in series with Id current. Please explain to me how Cs affects Io.
 
Jony130 said:
But Cs is in series with Id current. Please explain to me how Cs affects Io.
Yes, it's correct. I must have gotten confused somewhere but it's fine now
 
Do you have any more qestion about this amp?
1.1.png
 

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