Commutativity in the linear transformation space of a 2 dimensional Vector Space

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SUMMARY

The discussion centers on the commutativity of the matrix expression (C-D)2 with all 2x2 matrices, given that AB=C and BA=D for 2x2 matrices A and B. This property is established through Hall's identity, which states that the commutator [A,B] = AB-BA has a trace of zero, leading to the conclusion that [A,B]2 is a multiple of the identity matrix. The result does not extend to n x n matrices where n > 2 due to the differing characteristics of higher-dimensional matrices.

PREREQUISITES
  • Understanding of linear transformations in 2-dimensional vector spaces
  • Familiarity with matrix multiplication and properties of commutators
  • Knowledge of Hall's identity and its implications
  • Basic grasp of the Cayley–Hamilton theorem
NEXT STEPS
  • Study the properties of commutators in linear algebra
  • Explore Hall's identity in greater detail
  • Learn about the Cayley–Hamilton theorem and its applications
  • Investigate the behavior of commutativity in higher-dimensional matrices
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Mathematicians, students of linear algebra, and anyone interested in the properties of matrices and linear transformations in vector spaces.

quarkine
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A variant of a problem from Halmos :
If AB=C and BA=D then explain why (C-D)^2 is commutative with all 2x2 matrices if A and B are 2x2 matrices.
This result does not hold for any other nxn matrices where n > 2. Explain why.

Edit: I tried to show that ((C-D)^2) E - E((C-D)^2) is identically zero. But that didn't work.
A guess is that since the above matrix commute with any 2x2, it has to be of the form bI (where b is a scalar anad I the indentity), which can be confirmed by brute calculation but I am searching for a better way.
 
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quarkine said:
If AB=C and BA=D then explain why (C-D)^2 is commutative with all 2x2 matrices if A and B are 2x2 matrices.
This is known as Hall's identity. The proof, in very brief outline, goes like this. The commutator $[A,B] = AB-BA$ has trace zero. Its characteristic equation is therefore of the form $\lambda^2 = \mathrm{const.}$ It then follows from the Cayley–Hamilton theorem that $[A,B]^2$ is a multiple of the identity.
 

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