Commutators with powers? A 'show that' question

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SUMMARY

The discussion revolves around proving the commutator identity [AB,C] = A[B,C] + [A,C]B. Participants explore the application of commutators in the context of ring theory and Leibniz algebras. A user attempts to manipulate the expression using arbitrary commutators and test functions, ultimately deriving the identity through systematic rearrangement and application of known commutator identities. The proof is confirmed through logical steps involving common factor extraction and identity application.

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  • Understanding of commutators in algebra
  • Familiarity with ring theory concepts
  • Knowledge of Leibniz algebras
  • Basic skills in manipulating algebraic expressions
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  • Study the properties of commutators in quantum mechanics
  • Learn about ring theory fundamentals and its applications
  • Explore Leibniz algebras and their significance in mathematics
  • Practice proving identities involving multiple operators
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Students of advanced algebra, particularly those studying quantum mechanics or abstract algebra, as well as educators looking for examples of commutator identities in mathematical proofs.

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Homework Statement



The question is 'show that the commutator [AB,C]=A[B,C]+[A,C]B'

Homework Equations



I'm not sure, a search for a proof gave the names 'ring theory' and 'Leibniz algebra', but further searching hasn't provided a proof so far and it seems it is just accepted as a standard identity. Ring theory isn't on my syllabus and I haven't heard of it before today :|

The Attempt at a Solution



I tried applying the arbitrary commutators and I got ABC-CAB, and now I'm stuck lol as I can't arrange it to fit the above. Any help would be greatly appreciated, as I'm most likely going about it the wrong way, any identities for commutators with multiplied operators within them would be useful to know :P

Thanks :)
 
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Introduce a test function f:

[AB,C]f = ABCf - CABf = A([B,C]- CB)f + ([A,C]-AC)f

and work from there. Then just drop the test function f.
 
Thanks for the tip but I think I managed to do it without the test function (I think :P)

Could somebody please go over my workings to confirm if they are correct or not?

Expand:
[AB,C] = ABC - CAB

Sub in a factor of (ACB-ACB):
[AB,C] = ABC + (ACB - ACB) - CAB

Re-arrange:
(ABC - ACB) + (ACB - CAB)

Take out common factors:

A(BC - CB) + (AC - CA)B

Use commutator identities below:
A[B,C] = A(BC - CB)
[A,C]B = (AC - CA)B

Leading to A[B,C] + [A,C]B with any luck :P

Cheers :)
 

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