Compactness of closed unit ball

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Homework Help Overview

The problem involves the space l∞, which consists of bounded sequences of real numbers, and requires proving that the closed unit ball B(0, 1) is not compact. The context centers around concepts of compactness and sequential compactness in functional analysis.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of sequential compactness and the need to find a sequence in B(0, 1) that lacks a convergent subsequence. There is uncertainty about which specific non-convergent sequence to select and how to apply the norm in this context.

Discussion Status

Some guidance has been provided regarding the use of a sequence of sequences and the characteristics of the space l∞. Participants are exploring different examples and clarifying their understanding of the problem setup.

Contextual Notes

There is a noted confusion regarding the application of the complete norm and the nature of sequences in the space of bounded sequences.

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Homework Statement


Let l∞ be the space of bounded sequences of real numbers, endowed with the norm
∥x∥∞ = supn∈N |xn | , where x = (xn )n∈N .
Prove that the closed unit ball of l∞ , B(0, 1) = {x ∈ l∞ ; ∥x∥∞ ≤ 1} , is not compact.

Homework Equations





The Attempt at a Solution


I'm thinking about using the notion of sequential compactness, since every sequence Xn has an upper limit here, but I'm not sure if that would help much. Could anyone please give me a hint? Any input is appreciated!
 
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Sure, use the sequential form. Find a sequence in B(0,1) with no convergent subsequence.
 
thanks for the reply, but I'm still not sure about which non-convergent sequence to choose, would something like 1/n work? I just don't know how to use the complete norm here.
 
rainwyz0706 said:
thanks for the reply, but I'm still not sure about which non-convergent sequence to choose, would something like 1/n work? I just don't know how to use the complete norm here.

Remember what the space is here. It's the set of bounded sequences. So a point in your space is itself a sequence. Thus a sequence in your space must in fact be a sequence of sequences. Give me some examples.
 

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