Compare Mass-Pulley Frictionless Slope

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Homework Help Overview

The problem involves comparing the masses of objects on two frictionless slopes inclined at different angles (60 degrees and 30 degrees) to determine the conditions under which they do not slide. The context is rooted in mechanics, specifically dealing with forces on inclined planes.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss drawing free body diagrams for each block to analyze the forces acting on them. There is an emphasis on rewriting forces in terms of their components relative to the slopes.

Discussion Status

The discussion is ongoing, with participants providing hints and suggestions for refining the approach. There is acknowledgment of progress in understanding the problem, but no consensus or final solution has been reached yet.

Contextual Notes

Participants are working under the constraint of expressing their answers with two significant figures and are encouraged to explore the relationships between the forces involved.

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Homework Statement


If the left-hand slope in the figure makes a 60 degree angle with the horizontal, and the right-hand slope makes a 30 degree angle, how should the masses compare if the objects are not to slide along the frictionless slopes?

Express your answer using two significant figures.

Homework Equations



besides degrees of the angles, I am stuck on how to go about the problem. Any hints is appreciated. =]

The Attempt at a Solution



physics-2.png


Added both F.B.D:
tension-1.png


tension1.png
 
Last edited:
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Draw a free body diagram for each block.
 
frogjg2003 said:
Draw a free body diagram for each block.

Okay They are added. May you take a look and see if I am in the right direction?
 
Close, rewrite the forces in terms of their components parallel to and perpendicular to the slope. This leaves the normal forces only in the perpendicular directions, and the tension only in the parallel direction.
 
frogjg2003 said:
Close, rewrite the forces in terms of their components parallel to and perpendicular to the slope. This leaves the normal forces only in the perpendicular directions, and the tension only in the parallel direction.

oh okay I think I know what to fix. Thanks!
 
You're welcome.
 

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