Compare weights at equator and poles?

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SUMMARY

The weight of a 100kg person differs at the poles and the equator due to variations in gravitational force. At the poles, gravity is slightly stronger because of the shorter distance to the Earth's center. To calculate weight, one can use the formula "mg" while accounting for centrifugal force effects. For a more precise calculation, apply the formula "F = -(Gmm)/r^2" with adjusted values for the distances from the Earth's center to both the pole and the equator, factoring in Earth's rotation.

PREREQUISITES
  • Understanding of gravitational force and weight
  • Familiarity with the formula "F = -(Gmm)/r^2"
  • Knowledge of centrifugal force and its effects on weight
  • Basic concepts of Earth's shape and rotation
NEXT STEPS
  • Research the effects of latitude on gravitational force
  • Learn how to calculate weight variations using "mg" and centrifugal force
  • Explore the implications of Earth's oblate spheroid shape on gravity
  • Study the impact of Earth's rotation on weight measurements
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Students in physics, educators teaching gravitational concepts, and anyone interested in the scientific principles of weight variation due to Earth's shape and rotation.

cbere2013
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Hello,

I need some help understanding this question.
If we take a mass of a person as 100kg, what would he weigh at the poles and the equator, in Newtons? How do I do this please?

Thanks and much appreciate some help.
 
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The first thing you should think about is exactly what you mean by "weight"! Do you mean "what a spring scale would show if the person were to stand on it"? In that case you could, treating the Earth as a sphere, use "mg" but allow for the "centrifugal force" effect.

Taking the "squashed" shape of the Earth into effect, as mathman suggests, would be more accurate but much harder, requiring you to use "F= -(Gmm)/r^2" with different values for the distance from the center of the Earth to the pole and from the center of the Earth to the equator. And, of course, you should still allow for the apparent reduction in force due to the rotation of the earth.
 

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