Comparing Hall Voltage of Bars 1 & 2

  • Thread starter Thread starter bbuilder
  • Start date Start date
  • Tags Tags
    Voltage
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 replies · 2K views
bbuilder
Messages
14
Reaction score
0

Homework Statement



Two metal bars, 1 and 2, are identical in all ways, except that bar 2 has twice the width of 1. The bars are parallel to each other, but far apart from each other, in a uniform magnetic field and carry the same amount of current in a direction perpendicular to the field. How does the Hall voltage of bar 2 compare to that of bar 1?

Homework Equations


The equation for Hall effect is nq=(-JB/E). I know that I can relate E to V by using E=(V/d).


The Attempt at a Solution


If the width of bar 2 is twice the with of bar 1, then (because of E=V/d) the voltage of 2 would be two times greater than bar 1. I'm confused about why I need to use the Hall effect if I can just use E=V/d.
 
on Phys.org