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PhysicsTest

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- Homework Statement
- a. Find the magnitude of the Hall voltage VH in an n-type germanium bar used in fig, having majority-carrier concentration ND = 10^17 /cm^3. Assume Bz=0.1 Wb/m^2, d=3 mm, Ex=5V/cm.

b. What happens to VH if an identical p-type germanium bar having NA=10^17/cm^3 is used in part a?

- Relevant Equations
- ##V_H = Ed=Bvd = \frac{BJd} {\rho w} ##

The question is to find the Hall voltage

The magnetic field is in the +ve Z-direction, the electric field is in the +ve X-direction, the current will be in -ve Y direction.

There are many equations to find the hall voltages ##V_H = Ed=Bvd = \frac{BJd} {\rho w} ##. But i find the equation ##V_H = Ed## to solve and other parameters are not much of use.

a. n-type 4 will be more negative than 3 and ##V_H = 5*0.3V = 1.5V##

b. p-type 4 will be more positive than 3 and ##V_H = 5*0.3V = 1.5V##

Is the solution correct, or missing something?

The magnetic field is in the +ve Z-direction, the electric field is in the +ve X-direction, the current will be in -ve Y direction.

There are many equations to find the hall voltages ##V_H = Ed=Bvd = \frac{BJd} {\rho w} ##. But i find the equation ##V_H = Ed## to solve and other parameters are not much of use.

a. n-type 4 will be more negative than 3 and ##V_H = 5*0.3V = 1.5V##

b. p-type 4 will be more positive than 3 and ##V_H = 5*0.3V = 1.5V##

Is the solution correct, or missing something?