Complete set of solutions to the wave equation

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Discussion Overview

The discussion revolves around the complete set of solutions to the wave equation, specifically focusing on the separation of variables method and its relation to d'Alembert's solution. Participants explore different forms of solutions and their completeness in the context of one-dimensional wave equations.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant presents a solution using separation of variables, suggesting that Z(z) = acos(kz) + bsin(kz) and T(t) = ccos(ωt) + dsin(ωt) yield a product solution ZT, but questions its completeness.
  • Another participant proposes that the most general solution to the 1D wave equation is F(x, t) = f(x-ct) + g(x+ct), where f and g are arbitrary differentiable functions.
  • A third participant identifies the proposed general solution as d'Alembert's solution and emphasizes the initial query about separation of variables.
  • A later reply notes the importance of the relationship between ω and the wave speed, suggesting that linear combinations of solutions can reproduce d'Alembert's form through Fourier synthesis, indicating that both approaches may be complete and consistent.

Areas of Agreement / Disagreement

Participants express differing views on the completeness of solutions derived from separation of variables versus d'Alembert's solution. No consensus is reached regarding which form represents the most general solution.

Contextual Notes

There is an implicit assumption regarding the relationship between ω and the wave speed, which some participants highlight. The discussion also reflects a dependence on definitions of completeness in the context of wave solutions.

Thomas Rigby
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TL;DR
How to form the most general solution to the wave equation when using separation of variables?
I am solving the wave equation in z,t with separation of variables. As I understand it, Z(z) = acos(kz) + bsin(kz) is a complete solution for the z part. Likewise T(t) = ccos(ω t) + dsin(ωt) forms a complete solution for the t part. So what exactly is ZT = [acos(kz) + bsin(kz)][ccos(ωt) + dsin(ωt)]?
It does not appear to be the most general solution; I can only get a subset of the possible solutions of the form

Qcos(kz)cos(ωt) + Rcos(kz)sin(ωt) + Ssin(kz)cos(ωt)+Tsin(kz)sin(ωt).

I would think this latter would be the most general solution.
 
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I believe the most general solution to the 1D wave equation is F(x, t) = f(x-ct) + g(x+ct) , where f and g are any arbitrary (differentiable) functions.
 
That is known as d'Alembert's solution. I asked about separation of variables.
 
You neglected to mention that the omega on k had to equal the speed.
But any linear combination with various k is also is a solution and that will reproduce d'Alambert's form (via Fourier synthesis) and so both descriptions are complete and consistent..
 

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